A quantity of energy equal to 8.90 x 10^12 joules was emitted from a nuclear reaction. What amount of mass was required to be converted to yield this amount of energy? (1 J = 1 kg m2/s2)
Answers:

9.90 x 10^-5 kg

2.96 x 10^-4 kg

2.67 x 10^4 kg

8.01 x 10^5 kg

Question

A quantity of energy equal to 8.90 x 10^12 joules was emitted from a nuclear reaction. What amount of mass was required to be converted to yield this amount of energy? (1 J = 1 kg m2/s2)
Answers:
		
9.90 x 10^-5 kg
		
2.96 x 10^-4 kg
		
2.67 x 10^4 kg
		
8.01 x 10^5 kg

chmvijay · Answer

E=MC^2
M =E/C^2
where e is energy
c is velcity of light in vacuum
M= mass find it

anonymous · Answer

I tried that, but I got 1.008988764 x 10^28. just to be sure, e= 8.90 x 10^12, and c^2= 8.98 x 10^16, right?

chmvijay · Answer

M= 8.90 * 10^12 / (3 *10^8)^2
   =8.90*10^12 /9*10^16
   =0.98888*10^12-16
  =0.988*10^-4
   =9.888*10^-5
=9.9*10^-5

chmvijay · Answer

LOL u used formula wrong i think :)
M=E/C^2 is formula

anonymous · Answer

Thank you very much for you help!

chmvijay · Answer

y welcome