in horses, a trotter is dominant over a pacer and black is dominant over brown. What is the genotype of a black trotter whose mother was a brown pacer?
\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e~\color{#00ff00}t\color{#00ff49}o~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\) In genetics, the dominant trait is indicated with a capital and a recessive trait is indicated with a lowercase. So let's say we give the letter q to trotter/pacer and the letter b to black/brown Now a trotter is dominant over a pacer, so the trotter will be Q and the pacer will be q. For the color: black is dominant so it will be B, brown is recessive and will be b. Do you understand it so far?
understood so far
Okay then we'll continue :) Do you know the difference between homozygous and heterozygous?
Yes homozygous means it has 2 of the same trait like BB or bb and hetero Bb
correct :) So we have a black trotter. It has the 2 dominant traits so what can be the possible genotype?
QQBB or QqBb ?
yes! very good Now with this information we can determine the genotype of the father. We know the mother is a brown pacer, those are 2 recessive traits, so the genotype of the mother has to be qqbb. We can draw a punett square for this. |dw:1372236731095:dw| Can you fill in the rest? use the black box with the pencil in it on in the right upper corner of this drawing
@haseo729 are you still there?
Brown pacer =bt, black trotter =BT, combine these to gives BbTt, which is the required genotype
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