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Given: v \times \frac{dv}{dx} How would you determine that this is equal to: \frac{d}{dx} \left ( \frac{v^2}{2} \right ) ?
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Given: \[v \times \frac{dv}{dx}\] How would you determine that this is equal to: \[\frac{d}{dx} \left ( \frac{v^2}{2} \right )\]
Betting on the power rule and the chain rule (assuming v is some function of x, of course. and even if it isn't, this would still hold... ^_^ )
your question is perhaps what is the integral of vdv ?
\(v \times \dfrac{dv}{dx}=d\int v \times \dfrac{dv}{dx}=\dfrac{d}{dx}\int v dv=\dfrac{d}{dx}(\dfrac{v^2}{2}) \)
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