Determine two pairs of polar coordinates for the point (5, -5) with 0° ≤ θ < 360°
I know that it is (5sqrt2, an angle) then (-5sqrt2, an angle)
Well, that angle would have for its tangent, y/x Your y is -5 and x is 5 What's y/x?
-1
Good :) Now which angle(s) has a tangent of -1?
That IDK
Then, you can either use a scientific calculator (if permitted) or consult your unit circle again.
I can use a scientific calc, but what would i do ?
input \(\large \tan^{-1}(-1)\)
ohhh arctan!
yes, arctan.
okay one sec
its -45
The two angles are different right? so if one of them is -45 then what is the other?
-45? That's not within your bounds... 0° ≤ θ < 360°
okay then the flip of -45 is 315
Good :) And there's another angle for which tangent is -1. Unfortunately, your calculator can't help you with that :)
Unless....
never mind that other angle. Just know that there should be two possible angles. but we have more info... Your point (5,-5), in which quadrant is it?
IV right
Right. And 315 degrees, in which quadrant is that?
II I III IV so its in 4 ?
Yes :) So, it seems you lucked out and picked the correct quadrant :)
idk how to tell the quadrants of angles though
oh... 0-90 is 1 90-180 is 2 180-270 is 3 270-360 is 4
ohhh okay cool so then i was right :P
so it is in the fourth quadrant... what does thatmean for me?
It means you picked the correct angle. As I said before, there are two possible angles for which the tangent is -1 One is 315 degrees the other is 135 degrees. But 135 degrees is in quadrant II and your point (5, -5) is in quadrant IV so it has to be 315 degrees. Savvy? :D
ohhhhhhhhhhh! so i see! but then doesnt that make 135 the other angle?
It does :) Your intuition is brilliant :) The 'rejected' angle would be the angle for the coordinates with the 'negative' r :)
Got it! Thanks man! just one more on this wretched topic then ill be done. Can I tag you again?
Sure :)
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