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OpenStudy (anonymous):

Determine two pairs of polar coordinates for the point (5, -5) with 0° ≤ θ < 360°

OpenStudy (anonymous):

I know that it is (5sqrt2, an angle) then (-5sqrt2, an angle)

terenzreignz (terenzreignz):

Well, that angle would have for its tangent, y/x Your y is -5 and x is 5 What's y/x?

OpenStudy (anonymous):

-1

terenzreignz (terenzreignz):

Good :) Now which angle(s) has a tangent of -1?

OpenStudy (anonymous):

That IDK

terenzreignz (terenzreignz):

Then, you can either use a scientific calculator (if permitted) or consult your unit circle again.

OpenStudy (anonymous):

I can use a scientific calc, but what would i do ?

terenzreignz (terenzreignz):

input \(\large \tan^{-1}(-1)\)

OpenStudy (anonymous):

ohhh arctan!

terenzreignz (terenzreignz):

yes, arctan.

OpenStudy (anonymous):

okay one sec

OpenStudy (anonymous):

its -45

OpenStudy (anonymous):

The two angles are different right? so if one of them is -45 then what is the other?

terenzreignz (terenzreignz):

-45? That's not within your bounds... 0° ≤ θ < 360°

OpenStudy (anonymous):

okay then the flip of -45 is 315

terenzreignz (terenzreignz):

Good :) And there's another angle for which tangent is -1. Unfortunately, your calculator can't help you with that :)

terenzreignz (terenzreignz):

Unless....

terenzreignz (terenzreignz):

never mind that other angle. Just know that there should be two possible angles. but we have more info... Your point (5,-5), in which quadrant is it?

OpenStudy (anonymous):

IV right

terenzreignz (terenzreignz):

Right. And 315 degrees, in which quadrant is that?

OpenStudy (anonymous):

II I III IV so its in 4 ?

terenzreignz (terenzreignz):

Yes :) So, it seems you lucked out and picked the correct quadrant :)

OpenStudy (anonymous):

idk how to tell the quadrants of angles though

terenzreignz (terenzreignz):

oh... 0-90 is 1 90-180 is 2 180-270 is 3 270-360 is 4

OpenStudy (anonymous):

ohhh okay cool so then i was right :P

OpenStudy (anonymous):

so it is in the fourth quadrant... what does thatmean for me?

terenzreignz (terenzreignz):

It means you picked the correct angle. As I said before, there are two possible angles for which the tangent is -1 One is 315 degrees the other is 135 degrees. But 135 degrees is in quadrant II and your point (5, -5) is in quadrant IV so it has to be 315 degrees. Savvy? :D

OpenStudy (anonymous):

ohhhhhhhhhhh! so i see! but then doesnt that make 135 the other angle?

terenzreignz (terenzreignz):

It does :) Your intuition is brilliant :) The 'rejected' angle would be the angle for the coordinates with the 'negative' r :)

OpenStudy (anonymous):

Got it! Thanks man! just one more on this wretched topic then ill be done. Can I tag you again?

terenzreignz (terenzreignz):

Sure :)

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