2500 = x(0.045) + y(0.06) find x, find y
Is this supposed to be in parametric form, or is there a second equation?
guess so? its just 2500 = x(0.045) + y(0.06)
Hmmm.... because all that does is define a singe line. Perhaps they want it solved for x and solved for y.
yup
OK. Then you need to basically work with your order of operations, but from bottom up!
uh...?
Well, you know the order of operations? PEMDAS?
oh
so 2500 = x(.045) + y(.06) x = -(2500-0.6y)/0.045 right?
hmmmm.... \(2500 = x(.045) + y(.06)\implies \\ 2500-y(.06) = x(.045) + y(.06)-y(.06)\implies \\ 2500-y(.06) = x(.045)\implies \\ \left[2500-y(.06)\right]/(.045) = x(.045)/(.045)\implies \\ \left[2500-y(.06)\right]/(.045) = x \) \(\therefore x=\cfrac{2500-y(.06)}{.045}\)
Not sure how you got the - in front.
I tried that but it x turned to zero(0) (and so did y)
Well, an x of 0 does exist in that solution. So does a y of 0. That is, in that form, the answer for x.
but it wouldn't be equal to 2500
2500+0=2500 In this particular case, because of the decimals, the intercepts are at much larger numbers. This is the equation of a line. http://www.wolframalpha.com/input/?i=2500+%3D+x%280.045%29+%2B+y%280.06%29&dataset=
oh, thank you :)
So to find y, just do the same sort of moving things around. If there was a second equation for a second line, and they crossed, there would be one x and one y. But with just one equation, all you have is a line.
can x be also be found using derivatives?
All you will get with a derivative is the slope.
oh, thank you:)
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