Question

Find the product of the complex number and its conjugate. 3 + 3i

Answer 1

do you know what the conjugate is?

Answer 2

3 +3i I thought?

Answer 3

just change the sign to find the conjugate: 3-3i

Answer 4

is the answer 18?

Answer 5

now you just simply do \((3+3i)(3-3i)\)

Answer 6

yes :)

Answer 7

thank you so much, I have some other problems that I have finished, can you check them for me?

Answer 8

ok

Answer 9

How do i write the expression in standard form 3/3-12i?

And I got:
1/17 + 4i/17

Answer 10

\[\frac{3}{3-12i}\] ?

Answer 11

yes that is the question, and you have to write it in standard form.

Answer 12

oh ok

Answer 13

I got 1/17 + 4i/17

Answer 14

yep

Answer 15

alright, next is
Write the sum or difference in the standard form a + bi.
( 4 - 2i) + ( 9 + 6i)

And I got 13 + 4i

Answer 16

yes

Answer 17

( 9 + 5i)( 9 + 8i)

And I got;
41 + 117i

The possible answers are;
41 - 117i

40i2 + 117i + 81

121 - 27i

41 + 117i

Answer 18

your answer is correct

Answer 19

YOUR A FREAKING HERO

Answer 20

lol your welcome :)

Answer 21

I have 5 questions that I need help with if you know anyhting about the fundomental theorum of algebra