Mathematics
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OpenStudy (anonymous):
Simplify completely quantity x squared plus x minus 12 over quantity x squared minus x minus 20
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OpenStudy (anonymous):
here is the question in math terms
OpenStudy (anonymous):
can someone please help me with this i can't figure it out.
OpenStudy (anonymous):
anyone? please help
OpenStudy (anonymous):
x^2 +x-12\[\frac{ x^2 +x-12 }{ x^2-x-20 }\]
OpenStudy (anonymous):
factor the numerator and denominator
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OpenStudy (anonymous):
\[\frac{ (x-3)(x+4) }{ (x-5)(x+4) }\]
OpenStudy (anonymous):
x+4 cancels out
OpenStudy (anonymous):
left with (x-3)/(x-5)
OpenStudy (anonymous):
these are my only choices
OpenStudy (anonymous):
\[3\frac{ x^2-8x+15 }{ 4x^2-16x-20 }\]
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OpenStudy (anonymous):
this factors to
\[3\frac{ (x-5)(x-3) }{4(x-1)(x-5) }\]
OpenStudy (anonymous):
cancel out the x-5s
OpenStudy (anonymous):
left with \[\frac{ 3(x-3) }{ 4(x-1)}\]
OpenStudy (anonymous):
now divide this term by multiplying the reciprocal
OpenStudy (anonymous):
\[\frac{ x-3 }{ x-5 }*\frac{ 4(x-1) }{ 3(x-3) }\]
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OpenStudy (anonymous):
x-3s cancel out
leaving you with:\[\frac{ 4(x-1) }{ x-5 }\]
that's completely simplified
OpenStudy (anonymous):
the only choice i have like why you put is 4(x+1) not what u put
OpenStudy (anonymous):
dunno then