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If f(x)=7-x^2 and g(x)=x-4 ... [f*g](x)=?
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=f[g(x)] =f(g(x)= 7-(g... ? Is that right so far?
[f*g](x)= 7- (x-4)^2 solve it furhter
7-x^2-16?
is that right?
[f*g](x)= 7- (x-4)^2 = 7-(x^2+16-8x) do it further now
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where did 8x come from?
how would i get rid of the parentheses?
just multiply the negative sign with each term inside the parantheses
So... 7+x^2-112+56x
sorry: 7-x^2
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7-x^2-16+8x
how did you get 16 and 8? do you not multiply 7 to those numbers?
no i m not multiplying 7 to those numbers. i got 16 and 8 by the following formula \[(a-b)^{2} = a ^{2} +b ^{2}-2ab\]
so if I had [g#f](x) i would start it by saying x-4(7-x^2) right?
# is supposed to be *
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yes exactly
thanks so much!
welcome
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