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Solve for x: 3x-1/5 - 2x-4/3 = 1
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Get common denominators
15?
.. Or cancel them out
Yes, now multiply everything by 15 I thought you were better than that Nurali
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That wasn't it, @Nurali, its a whole number. But thanks.:)
Everything? Including numerators and denominators?
Do I plug 15 into x?
\[15[\frac{ 3x-1 }{ 5 }-\frac{ 2x-4 }{ 3 }]=1*15\]
I multiplied everything but I'm still a little confused.
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\[\frac{ 3x-1 }{ 5 }-\frac{ 2x-4 }{ 3 }=1\] \[\frac{ 3(3x-1)-5(2x-4) }{ 5*3 }=1\] \[\frac{ 9x-3-10x+20 }{ 15 }=1\] \[\frac{ -x+17 }{ 15 }=1\] \[-x+17=15\] \[x=17-15\] \[x=2\]
.. Thank you Nurali
Okay good that's what I got. Thank you both!
My Pleasure.
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