Question

Write the answer in both standard and slope intercept form.

contains (-2,3) (1,4) ?

Answer 1

\[y-y_1 = m(x-x_1)\]is standard form

Answer 2

\[y=mx+b\]is slope intercept form, where m is slope and b is the y-intercept

Answer 3

can you explain that? what numbers would i use to plug in?

Answer 4

\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\]
use this equation to find the slope first

you have 2 sets of points (x1, y1) and (x2, y2)
which are (-2,3) (1,4) in this case

Answer 5

find your slope, then use the standard form to find an equation. then convert it to slope intercept form

Answer 6

so: 4-3 over 1- -2 = m

Answer 7

yes

Answer 8

1/3 should be your slope

Answer 9

yep that';s what i got. so what would i use to plug in for my slope intercept: y=mx+b? i know m is 1/3

Answer 10

well lets do standard form first

find the standard form equation, and then use that to solve for y by itself, which should give you the slope intercept form

Answer 11

Ax+By=C

Answer 12

that is the general form, not standard form

Answer 13

y-y1=m(x-x1) ?

Answer 14

yes, use the m that you found and your points

plug them in and you have standard form of the line

Answer 15

y-3=1/3(x- -2)

Answer 16

yes, that is the equation for the line in standard form

Answer 17

now solve for y

Answer 18

you will have to distribute the 1/3

Answer 19

ok

Answer 20

y=1/3x^2 + 2/3x +3

Answer 21

no, where did you get x^2 from?

Answer 22

remember, you're multiplying by just 1/3, not 1/3x

Answer 23

1/3x(x+2)
i distributed 1/3x to the x. (1/3*x) and then did 1/3*2

Answer 24

it is not 1/3x(x+2)

it is 1/3(x+2)

you're adding an x that is not there

Answer 25

oh. i get it. so y=1/3x + 2/3x + 3
and then i would add 1/3x to 2/3x and get 1
so y=x+3 ?

Answer 26

you're distributing wrong

1/3(x+3) becomes 1/3x +2/3

y-3 = 1/3x+2/3

y = 1/3x+2/3+3

y = 1/3x +11/3

Answer 27

oh. so that is the standard form?

Answer 28

m = (y2 - y1) / (x2 - x1) ...set 1 (-2,3) set 2 (1,4)
m = (4 - 3)/ (1 - (-2)
m = 1/3

slope intercept form : y = mx + b
using slope 1/3 and either point....I will use (1,4)
y = mx + b
4 = 1/3(1) + b
4 = 1/3 + b
4 - 1/3 = b
12/3 - 1/3 = b
11/3 = b
so your slope intercept form of the equation becomes :
y = 1/3x + 11/3

Standard form : Ax + By = C
y = 1/3x + 11/3
-1/3x + y = 11/3 (multiply by 3)
-x - 3y = 11 (now multiply by -1 to make x positive)
x + 3y = -11
so your standard form is :
x + 3y = - 11

Answer 29

do you have any questions ?

Answer 30

oops...I messed up
standard form
y = 1/3x + 11/3
-1/3x + y = 11/3 (multiply by 3)
-x + 3y = 11 (now multiply by -1 to make x positive)
x - 3y = - 11

Thats better :)