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Find the values of a and b if the tangent line to f(t)=t^3+at+b at t=3 is y=5t-7.
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\[f \left( t \right)=t ^{3}+at+b\] \[f \prime \left( t \right)=3t ^{2}+a\] \[at t=3,f \prime \left( t \right)=3\left( 3 \right)^{2}+a=27+a\] slope of tangent at t=3 is 27+a Also eq. of tangent is y=5t-7 \[\frac{ dy }{dt}=5,at t=3,slope of line =5\] 27+a=5 a=-22 at t=3,y=5*3-7=8 \[Hence 8=3^{3}-22*3+b\] 8=27-66+b b=8+66-27=74-27=47
Thank you so much! I was lost on how to begin this and I can see I even attempted the problem wrong.
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