Question

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = - 16t2 + 704t. After how many seconds does the projectile take to reach its maximum height? Show your work for bette understandng please!!

Answer 1

Quadratic equation in standard form \[ax^2 +bx+c\]
a=-16
b=704
c=0
Find the maximum value x value->\[\frac{ -b }{ 2a }\]
\[\frac{ -704 }{ 2(-16)}\]=22 seconds
To find maximum height, plug in x value (time).
-16(22^2)+704(22)=7744 ft