Question

Find the axis of symmetry of the graph of the function.

f(x) = 2x^(2) - 12x + 19

Answer 1

use the formula :
x = -b/(2a)

Answer 2

f(x) = 2x^(2) - 12x + 19
here known a = 2, b = -12, and c = 19

Answer 3

x= -b/2a = -(-12)/(2*2) = 12/4 = 3

Answer 4

thank you!!

Answer 5

your equation is \(\large y = 2x^2-12x+19\)

Identify your a,b,c : \(\large a = 2 \ , \ b= -12 \ , \ c= +19\)

formula for axis of symmetry: this is the point on your x-axis where the points on your parabola are symmetric. In order to find this, follow the formula, \(\large x= -\frac{b}{2a}\)

We know our points, so just plug them into the formula \[\large x= -\frac{b}{2a}\]\[\large x= -\frac{-12}{2(2)} \]\[\large x= \frac{12}{4}\]\[\large x = 3\]
your parabola on the left and right side of x=3 will be symmetrical.