Question

I am working on finding the slope. The graph for y is -1,7 and the x is 9,-5, so y1 -x1 is the rise and x1 --5, is this correct?

Answer 1

are the coordinates \((9,-1)\) and \((-5,7)\) ?

Answer 2

No. The coordinates are y is -1,7 and x is 9,-5

Answer 3

this doesn't really make sense the way you wrote it
is one point \((-1,7)\) and the other point \((-9,-5)\) ?

Answer 4

I went to the left -1 and up to 7 for the y

Answer 5

x I went to the right over to 9 and down to -5 where the line passes through. The is a negative slope left to the right.

Answer 6

ok i think there might be some confusion here
the first coordinate is the \(x\) coordinate, the second coordinate is the \(y\) coordinate
so "left -1 up 7" is the point \((-1,7)\) and in this case the \(x\) coordinate is \(-1\) and the \(y\) coordinate is \(7\)

Answer 7

Okay you are right I guess I am confused.

Answer 8

the second point would be \((9,-5)\) and in that one the \(x\) coordinate is \(9\) and the \(y\) coordinate is \(-5\)

Answer 9

typo there, i meant
\[(-1,7),(9,-5)\\(x_1,y_1), (x_2, y_2)\]

Answer 10

lol...Okay, this makes a little more sense...I will try it now...to find the slope I need to subtract the x1 and x2?

Answer 11

there is a formula you can use, but before we use it, lets think
from \(-1\) to \(9\) is right \(10\) units
from \(7\) to \(-5\) is down \(12\) units

right 10, down 12, slope is \(-\frac{12}{10}=-\frac{6}{5}\)

Answer 12

formula you can use to get the same thing is
\[m=\frac{y_2-y_1}{x_2-x_1}\]

Answer 13

but make sure to subtract the \(y\) from one coordinate from the \(y\) from the other
don't subtract \(x\)'s from \(y\)'s

Answer 14

That is what I was looking for....my rise would be y2 -y1 and my run is x2-x1, correct?

Answer 15

yes

Answer 16

I undestand clearly, I was mixing the x and the y ....thanks

Answer 17

yw