Question

sin Ɵ / 1 + sin Ɵ - sin Ɵ / 1 - sin Ɵ
Complete the identity ..

Answer 1

\[\frac{ \sin \theta }{ 1+\sin \theta }-\frac{ \sin \theta }{ 1-\sin \theta }\]

Answer 2

Is this your problem?

Answer 3

Yeah !

Answer 4

Okay, first what we do is get common denominators. Can you do that?

Answer 5

\[\cos^2 \theta \] ?

Answer 6

Close enough: 1-sin^2x

Answer 7

wait how did you get that?

Answer 8

\[\frac{ \sin \theta (1- \sin \theta)-\sin \theta(1+\sin \theta) }{ (1-\sin \theta)(1+\sin \theta) }\]

Answer 9

@shamim illustrates it, thank you for that!

Answer 10

\[\frac{ \sin \theta (1-\sin \theta-1-\sin \theta) }{ 1-\sin ^{2}\theta }\]

Answer 11

I'm so confused....

Answer 12

@shamim can take care of you from here. Call if you need anything!

Answer 13

where u confused

Answer 14

What is the first step ?

Answer 15

\[\frac{ -2 \sin ^{2}\theta }{ \cos ^{2}\theta }\]

Answer 16

ohh ok so you get -2tan^2 theta
but i dont know how to get to there

Answer 17

ok

Answer 18

just follw my every step

Answer 19

go back

Answer 20

how did it turn in multiplication?

Answer 21

u know\[(a+b)(a-b)=a ^{2}-b ^{2}\]

Answer 22

do u know this formula?

Answer 23

oh yeah

Answer 24

OHHHHHHHHHHHHHHH I SSEE NOW

Answer 25

then\[(1+ \sin \theta)(1- \sin \theta)=1^{2}-\sin ^{2}\theta\]

Answer 26

\[\sin \theta(1-\sin \theta-1-\sin \theta) / 1-\sin^2 \theta \] im stuck here

Answer 27

):

Answer 28

where did the -2sin^2 theta come from ?

Answer 29

Did he leave?

Answer 30

I think so... got tired of my dumbness :C

Answer 31

No, you're not dumb at all.

Answer 32

But I can try to finish it if you want?

Answer 33

Ok please thank you

Answer 34

Where did you guys leave off at?

Answer 35

I dont know where to go after
sinƟ(1-sinƟ-1-sinƟ) / cos^2Ɵ

Answer 36

how did the top part turn in -2sin^2Ɵ ?

Answer 37

Well using HIS method: