Question

Let f(x)=|x| and g(x)=[x].
Evaulate:

Answer 1

(fog)(-5/3)-(gof)(-5/3)

Answer 2

isn't @ParthKohli enough for this? :|

Answer 3

I am getting zero :(

Answer 4

@terenzreignz @amistre64

Answer 5

it must be one :)

Answer 6

how?

Answer 7

What is [x]? Like \(\lfloor x \rfloor\)

Answer 8

gINT

Answer 9

fog(x) = |[x]|
fog(-5/3) = fog(-1.67)
the greatest integer function for -1.67 gives -2.. taking absolute value.. we get fog(-5/3) = 2

gof(x) = [|x|]
gof(-5/3) = fog(-1.67
the absolute value will be 1.67 and it's greatest integer function value will be 1..

So 2-1 = 1 :D

Answer 10

[1.67] should be 1..

Answer 11

http://www.wolframalpha.com/input/?i=floor%281.67%29

Answer 12

1-1 is 0

Answer 13

but its negative of 1.67 man !

Answer 14

oh yeah!sorryy!

Answer 15

okay,got it :P