A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele?
(p + q = 1, p2 + 2pq + q2 = 1)

is it (A. p=0.65, q=0.35 (B. p=0.25, q=0.75 (C. p=0.4, q=0.6

Question

A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice are homozygous black and 24% are heterozygous black, what would be the frequency of each allele?
(p + q = 1,  p2 + 2pq + q2 = 1)

is it (A. p=0.65, q=0.35 (B. p=0.25, q=0.75 (C. p=0.4, q=0.6

anonymous · Answer

its answer c

thomaster · Answer

$\Huge\tt \color{#CC0000}W\color{#CD0B00}e\color{#CF1700}l \color{#D12200}c\color{#D32E00}o\color{#D53900}m\color{#D74500}e~\color{#DB5C00}t\color{#DD6800}o~\color{#E17F00}O\color{#E38B00}p\color{#E59600}e\color{#E7A200}n\color{#E9AD00}S\color{#EBB900}t\color{#EDC500}u\color{#EFD000}d\color{#F1DC00}y\color{#F3E700}!\color{#F5F300}!$

Do you still need help with this problem?

anonymous · Answer

no but thanks.

thomaster · Answer

Okay :)
If you're having trouble with another question, don't hesitate to ask for help $\huge ツ$