Mathematics
8 Online
OpenStudy (anonymous):
Consider the functions f(x) = x2 − 13 and g(x) = x + 5. What is the value of (f + g)(3)?
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OpenStudy (anonymous):
@ivettef365
OpenStudy (ivettef365):
ok you can add both functions first and then substitute the x for 3
or you can substitute on both functions the x for 3 and then add the results
OpenStudy (anonymous):
Question is quite simple since both are functions of x then (f+g)(x)=f(x)+g(x)
so (f+g)(x)=2x-13+x+5
(f+g)(x)=3x-8
(f+g)(3)=3x3-8=9-8=1
OpenStudy (ivettef365):
ipm sorry but that is wrong because is no 2x, it is x^2
OpenStudy (anonymous):
ya 1 is not an answer
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OpenStudy (ivettef365):
so you have x^2 -13 +x +5
OpenStudy (ivettef365):
that is equal to
x^2 +x -8 now substitute the x for 3 and what do you get
OpenStudy (anonymous):
@ivettef365 not my fault in the question it was not given raised to the power
OpenStudy (anonymous):
sorry
OpenStudy (ivettef365):
so what are the equations
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OpenStudy (anonymous):
-32?
OpenStudy (anonymous):
its x^2
OpenStudy (anonymous):
@ivettef365
OpenStudy (ivettef365):
you are talking about f(x) right
OpenStudy (anonymous):
no the x right after that
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OpenStudy (ivettef365):
ok the problems are:
f(x) = x^2 -13 and g(x) = x +5
OpenStudy (anonymous):
yes
OpenStudy (ivettef365):
ok, then it was correct all alone, so we have
x^2 +x-8, substitute x for 3 what do you get
OpenStudy (anonymous):
-4?
OpenStudy (ivettef365):
actually positive 4
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OpenStudy (ivettef365):
you have
(3)^2 +(3) - 8
9 +3 -8 = ??
OpenStudy (anonymous):
4 becuz the 12 is bigger
OpenStudy (ivettef365):
correct
OpenStudy (anonymous):
yes! ty
OpenStudy (ivettef365):
yw :)