A certain arithmetic sequence has the recursive formula an = an-1 + d. If the common difference between the terms of the sequence is -13, what term follows the term that has the value 13?
\[\bf a_n=a_{n-1}+d \rightarrow a_n =13-13=?\]
@myesha12
yes
what's the answer? I typed everything up. @myesha12
What goes in the place of the question mark
i don't know that's what i was tying to figure out
Ok basically the recursive sequence here tells us that the next term in the sequence is the previous term plus the common difference. Here we are finding the term after 13; \(\bf a_n\). So to find the term \(\bf a_n\) which comes right after 13, by the recursive sequence, we have to take the term that comes before \(\bf a_n\) and that term is 13. And we must add the common difference \(\bf d=-13\) to 13 to get \(\bf a_n\). So \(\bf 13+(-13)=13-13=0\). Get it? @myesha12
yes!!! THANK YOU
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