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Mathematics 15 Online
OpenStudy (anonymous):

Projection matrices.

OpenStudy (anonymous):

OpenStudy (amistre64):

without knowing any thrm that relate to that, it just looks like a mess to me

OpenStudy (anonymous):

I got a hint from my teacher: The targets are orthogonal complements. then use the fact that you have projection matrices.

OpenStudy (phi):

How about this? let x be a vector in \( \Re ^7\) we can decompose it into \( n \in N(A^T) \) and \( c \in C(A) \) x= n + c for all x: PQx = PQ(n+c) = PQn + PQc Qn = n (n is in the null space of A transpose) Qc = 0 ( c is not in the null space) so we have Pn + 0 Pn = 0 (n is not in the column space of P) so we have PQx = 0 for all x --> PQ= O for all vectors x: (P+Q)x = (P+Q)(n+c)= Pn + Qn + Pc + Qc Pn= 0 (n is not in the column space of A) Qn = n Pc = c Qc =0 we get (P+Q)x = n+c = x which implies P+Q = I

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