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Mathematics 21 Online
OpenStudy (anonymous):

plse solve thissss

OpenStudy (anonymous):

help me on my question please!

ganeshie8 (ganeshie8):

use this :- starting from 5, every integer factorial has 0 in its units place

ganeshie8 (ganeshie8):

All you have to do is to find last digit of, 1! + 2! + 3! + 4!

OpenStudy (anonymous):

1 2 6 24

OpenStudy (anonymous):

total of 1+2+6+24=33

ganeshie8 (ganeshie8):

Yes. just take the last digit of that

ganeshie8 (ganeshie8):

cuz for numbers greater than 4, last digit is 0. so they wont affect the last digit.

OpenStudy (anonymous):

33

ganeshie8 (ganeshie8):

last digit is just 3

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

what after that

ganeshie8 (ganeshie8):

Nothing. we're done. last digit is 3.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

@ganeshie8 thank u

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

you want to know the logic?

ganeshie8 (ganeshie8):

yw!

OpenStudy (loser66):

\[1! =1\\2! = 1!*2 =1*2=2\\3!= 2!*3=2*3=6\\4!=3!*4=6*4=24\\5!=4!*5=24*5 = 120\\6!=5!*6= 720\] pay attention at 5! since the last digit of 5! is 0 so, the next term will have the last digit is 0 therefore, your last digit is counted from the first four terms.

OpenStudy (loser66):

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