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Mathematics 15 Online
OpenStudy (anonymous):

Help!! http://prntscr.com/1c95zm

OpenStudy (whpalmer4):

\[y + 1/y = 4\]Solve that for \(y\) by multiplying both sides by \(y\) \[y^2 + 1 = 4y\]Now you've got a quadratic which you should be able to solve. Take the answers you get and plug them into the other expression and see what you get.

OpenStudy (shubhamsrg):

or, why don't you write y^2 + 1/y^2 as y^2 + 1/y^2 + 2 - 2 see if this helps ?

OpenStudy (anonymous):

@shubhamsrg issay se kya karun? :@

OpenStudy (shubhamsrg):

(y^2) + (1/y)^2 + 2(y)(1/y) - 2 you see an identity hidden somewhere over there? :O

OpenStudy (anonymous):

no i am not getting this :@

OpenStudy (shubhamsrg):

You understand how I expressed your given equation in this form ? I mean everything till now is clear ?

OpenStudy (anonymous):

no :P

OpenStudy (shubhamsrg):

y^2 + 1/y^2 = (y)^2 + (1/y)^2 = (y)^2 + (1/y)^2 + 2 -2 . You must be comfortable till here ?

OpenStudy (anonymous):

yeah!

OpenStudy (shubhamsrg):

I wrote 2 as 2(y)(1/y)

OpenStudy (shubhamsrg):

which brings us to (y)^2 + (1/y)^2 + 2(y) (1/y) -2

OpenStudy (anonymous):

yeah...

OpenStudy (shubhamsrg):

can you tell me expansion of (y + 1/y)^2 ?

OpenStudy (anonymous):

y2+2+1/y2

OpenStudy (shubhamsrg):

yes, and what have we written above ?

OpenStudy (anonymous):

oh ok now i get this!

OpenStudy (shubhamsrg):

glad you do (Y)

OpenStudy (whpalmer4):

so what's the answer? prove that you get it :-)

OpenStudy (shubhamsrg):

perhaps we took a longer road, what you could have easily understood was, squaring both sides in (y+1/y) =4

OpenStudy (anonymous):

-.- why didn't you give me this easy explanation before?

OpenStudy (shubhamsrg):

hmm, both things are same.

OpenStudy (shubhamsrg):

what? should I apologize? :P

OpenStudy (anonymous):

nah! i'll spare you :) but could you continue your longer explanation, i mean how would it lead to the same answer?

OpenStudy (shubhamsrg):

(y+1/y)^2= 4^2 y^2 + 1/y^2 + 2 = 16 so y^2 + 1/y^2 = ...

OpenStudy (shubhamsrg):

and thanks for sparing me .-.

OpenStudy (anonymous):

(y)^2 + (1/y)^2 + 2 -2 ye wali eq kaisay 16 answer de gi?

OpenStudy (shubhamsrg):

nahi, dono 14 denge! o.O

OpenStudy (anonymous):

kaisayy??

OpenStudy (shubhamsrg):

(y + 1/y)^2 -2 first case me =14 2nd case me to 14 hai hi clearly

OpenStudy (anonymous):

ah ok i am sorry i got this now :P

OpenStudy (shubhamsrg):

(Y)

OpenStudy (whpalmer4):

they threw you a little curve ball with the answer choices :-)

OpenStudy (anonymous):

yeah !

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