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Mathematics 14 Online
OpenStudy (anonymous):

[6.01] Select the system of equations that corresponds to the given graph. http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v10/06_04_08.jpg 4x + y = 6 6x + 3y = 6 −3x + y = 2 4x + 2y = 4 2x + y = 4 6x + 3y = 12 4x + 2y = 6 6x + 3y = 12 help me

OpenStudy (whpalmer4):

In general, if you post a link to a system where you have to log in, someone who is not a user of that system will not be able to see the thing to which you linked.

OpenStudy (anonymous):

oh sorry

OpenStudy (whpalmer4):

But no matter, I'll how to do it! You've got a pile of equations, and a graph. You want to see which equations go with the graph. The easy way to do it is to plug in x=0 and find the value of y that makes it true, giving you the point (0,y-intercept) and then do the same thing, plugging in y = 0 and find the value of x that makes it true, giving you the point (x-intercept, 0). Now look for the graph where the line goes through those two points!

OpenStudy (anonymous):

OpenStudy (whpalmer4):

Let's take \[4x+y=6\]First set x = 0 \[4(0)+y=6\]\[0+y=6\]\[y=6\]so one point is \((0,6)\) Now do the same except with y = 0 \[4x + 0 = 6\]\[4x=6\]\[x=6/4\]so the other point is \((6/4,0)\) so that is the equation of a line which passes through (0,6) and (6/4,0)

OpenStudy (whpalmer4):

a quick glance at the graph you provided shows that it is not the equation of either of the lines.

OpenStudy (whpalmer4):

so that means we can disregard any answer choice which contains that equation.

OpenStudy (whpalmer4):

let me know which choice you make and I'll check it for you

OpenStudy (anonymous):

I think this one 4x + 2y = 4 2x + y = 4

OpenStudy (anonymous):

"isolate y" means "rearrange the equation so it begins y = ..." 4x - y = 8 subtract 8 from both sides of equation 4x - y - 8 = 0 add y to both sides of equation 4x - 8 = y which you can flip around to y = 4x - 8 Now, there is no 4x - 8 in the choices, but 4x - 8 = -8 + 4x Rearrange first to 4x -8 = y or y = -8 + 4x and substitute this. So the third choice is the correct answer. Am i right????

OpenStudy (whpalmer4):

4x + 2y = 4 and 2x + y = 4 okay, let's find the intercepts: 4(0) + 2y = 4 2y = 4 y = 2 (0,2) is one point 4x+2(0) = 4 4x=4 x=1 (1,0) is the other point The line sloping upper left to lower right goes through (0,2) and (1,0) so 4x+2y=4 is the graph of that equation. so far so good.

OpenStudy (anonymous):

I am so sorry wrong thing so sorry for that

OpenStudy (whpalmer4):

the other equation: 2x+y=4 2(0) + y = 4 y = 4 (0,4) is one point that is not crossed by the other line, so this is not the correct set of equations.

OpenStudy (whpalmer4):

so pick a different answer choice that contains 4x + 2y = 4

OpenStudy (anonymous):

this 4x + 2y = 6 6x + 3y = 12

OpenStudy (whpalmer4):

again, let's find the intercepts: 6(0) + 3y = 12 y = 4 (0,4) 6x+3(0) = 12 x=2 (2,0) unfortunately, neither line appears to pass through both of those points...so that is not correct.

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