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Find the value of k so that a line passing through (k, k – 3) and (–2, 4) has a slope of 1/4 A. –3 B. 2 C. 5 D. 10
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Can anyone please explain how to solve?
I got you!
You have to use the slope-intercept form formula: \[\frac{ 4-(k-3) }{ -2-k }=\frac{ 1 }{ 4 }\] Can you handle it from here?
1-k / -2-k = 1/4
Is this correct?
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@Luigi0210
Not exactly.. did you distribute your negative?
7-k/-2-k = 1/4
Is this correct?
There you go
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I don't know how to continue though:(
Cross multiply
28-4k/ -2-k is what i got
Is it correct?
good so far, keep going
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I am not sure should I divide or what?
\[\frac{ 7-k }{ -2-k }=\frac{ 1 }{ 4 }\] \[-2-k=28-4k\]
does k=10?
Why yes, yes it does
Thaaaank yooou:)
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