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Chemistry 15 Online
OpenStudy (anonymous):

A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 ∞C/m? Show all of the work needed to solve this problem.

OpenStudy (aaronq):

use this equation: \[\Delta T = i*m*K _{f}\]

OpenStudy (aaronq):

where the change in temperature (of the freezing point) is equal to the product of the van't hoff factor (for glucose it's 1) times the molality of the solution times the freezing point depression constant.

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