Question

Write the equation of the line that passes through (1, 3) and (4, 4) in standard form.

3x – 3y = –8

x – 3y = –9

x – 3y = –8

3x + y = 9

Answer 1

You got this! You've done them before.

Answer 2

i dont got this @Luigi0210

Answer 3

Yes you do! >.<
Okay, first let's find the slope

Answer 4

wait is it A??

Answer 5

luigiiiiiiii

Answer 6

What? oh sorry about that. Hold on.

Answer 7

\[\frac{ 4-3 }{ 4-1 }=\]

Answer 8

1/3

Answer 9

i'm pretty sure the answer is a

Answer 10

Nope :/

Answer 11

huh....

Answer 12

please just tell me the answer luigi i've been working on this for like 3 hours straight ):

Answer 13

So we have the slope right? and points, so let's plug that into the point slope formula.
\[y-3=\frac{ 1 }{ 3 }(x-1)\]
Now distribute and solve:
\[y-3=\frac{ 1 }{ 3 }x-\frac{ 1 }{ 3 }\]
Add 3:
\[y-3(+3)=\frac{ 1 }{ 3 }x-\frac{ 1 }{ 3 }+(\frac{ 9 }{ 3 })\]
\[y=\frac{ 1 }{ 3 }x+\frac{ 8 }{ 3 }\]
Now get it in standard form: ax+by=C
\[-\frac{ 1 }{ 3 }x+y=\frac{ 8 }{ 3 }\]
We have a negative fraction, and a cannot be negative nor a fraction so we have to get rid of it by multiplying it by -3 to both sides:
\[-3(\frac{ -1 }{ 3 }x+y)=-3*(\frac{ 8 }{ 3 })\]
That gives us:
\[x-3y=-8\]

Answer 14

awwww thanks luigi you're the bomb

Answer 15

^_^' Just here to help.

Answer 16

you're awesome! :)