Write the equation of the line given by the following graph in standard form.
2x – y = –1
2x + y = –1
2x + y = 1
2x – y = 1
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
identify two points that lie on that line
jimthompson5910 (jim_thompson5910):
then plug each point into each answer choice
if both points make the equation true, then the equation is the answer
OpenStudy (anonymous):
what are the two points
jimthompson5910 (jim_thompson5910):
one point is (0,1)
what's another?
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OpenStudy (anonymous):
no idea
OpenStudy (anonymous):
im terrible at this
jimthompson5910 (jim_thompson5910):
how about (1,-1)
see how I'm getting these two points?
jimthompson5910 (jim_thompson5910):
and that's ok, that's why there's practice
OpenStudy (anonymous):
yes i do
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jimthompson5910 (jim_thompson5910):
ok so let's just focus on (0,1) for now
OpenStudy (anonymous):
alrighty
jimthompson5910 (jim_thompson5910):
if we plug it into choice A, then we get
2x – y = –1
2(0) – 1 = –1 ... replace x with 0 and y with 1
0 - 1 = -1
-1 = -1
so that's true
This means that (0,1) is definitely on 2x – y = –1
OpenStudy (anonymous):
alright cool
jimthompson5910 (jim_thompson5910):
now let's focus on (1,-1)
plug it into choice A to get
2x – y = –1
2(1) – (-1) = –1 .. plug in x = 1 and y = -1
2 + 1 = -1
3 = -1
this is false, so (1,-1) is NOT on the line 2x – y = –1
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jimthompson5910 (jim_thompson5910):
so 2x – y = –1 goes through (0,1) but it does NOT go through (1,-1)
OpenStudy (anonymous):
so A is incorrect
jimthompson5910 (jim_thompson5910):
yep, it needs to go through both points to work
OpenStudy (anonymous):
alright so B
jimthompson5910 (jim_thompson5910):
what do you get when you plug in (0,1) into the equation for choice B?
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OpenStudy (anonymous):
2x + y = -1
2 (0) + 1 = -1
0 + 1 = -1
1 = -1
so that is incorrect
OpenStudy (anonymous):
right?
jimthompson5910 (jim_thompson5910):
very good
jimthompson5910 (jim_thompson5910):
that rules out B
OpenStudy (anonymous):
so the answer is C
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jimthompson5910 (jim_thompson5910):
(0,1) works because
2x + y = 1
2(0) + 1 = 1
0 + 1 = 1
1 = 1
is true
------------------
let's check out (1,-1)
2x + y = 1
2(1) + (-1) = 1
2 - 1 = 1
1 = 1
and that works too
both points are confirmed to be on this line, so 2x + y = 1 is definitely the answer