Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Write the equation of the line given by the following graph in standard form. 2x – y = –1 2x + y = –1 2x + y = 1 2x – y = 1

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

identify two points that lie on that line

jimthompson5910 (jim_thompson5910):

then plug each point into each answer choice if both points make the equation true, then the equation is the answer

OpenStudy (anonymous):

what are the two points

jimthompson5910 (jim_thompson5910):

one point is (0,1) what's another?

OpenStudy (anonymous):

no idea

OpenStudy (anonymous):

im terrible at this

jimthompson5910 (jim_thompson5910):

how about (1,-1) see how I'm getting these two points?

jimthompson5910 (jim_thompson5910):

and that's ok, that's why there's practice

OpenStudy (anonymous):

yes i do

jimthompson5910 (jim_thompson5910):

ok so let's just focus on (0,1) for now

OpenStudy (anonymous):

alrighty

jimthompson5910 (jim_thompson5910):

if we plug it into choice A, then we get 2x – y = –1 2(0) – 1 = –1 ... replace x with 0 and y with 1 0 - 1 = -1 -1 = -1 so that's true This means that (0,1) is definitely on 2x – y = –1

OpenStudy (anonymous):

alright cool

jimthompson5910 (jim_thompson5910):

now let's focus on (1,-1) plug it into choice A to get 2x – y = –1 2(1) – (-1) = –1 .. plug in x = 1 and y = -1 2 + 1 = -1 3 = -1 this is false, so (1,-1) is NOT on the line 2x – y = –1

jimthompson5910 (jim_thompson5910):

so 2x – y = –1 goes through (0,1) but it does NOT go through (1,-1)

OpenStudy (anonymous):

so A is incorrect

jimthompson5910 (jim_thompson5910):

yep, it needs to go through both points to work

OpenStudy (anonymous):

alright so B

jimthompson5910 (jim_thompson5910):

what do you get when you plug in (0,1) into the equation for choice B?

OpenStudy (anonymous):

2x + y = -1 2 (0) + 1 = -1 0 + 1 = -1 1 = -1 so that is incorrect

OpenStudy (anonymous):

right?

jimthompson5910 (jim_thompson5910):

very good

jimthompson5910 (jim_thompson5910):

that rules out B

OpenStudy (anonymous):

so the answer is C

jimthompson5910 (jim_thompson5910):

(0,1) works because 2x + y = 1 2(0) + 1 = 1 0 + 1 = 1 1 = 1 is true ------------------ let's check out (1,-1) 2x + y = 1 2(1) + (-1) = 1 2 - 1 = 1 1 = 1 and that works too both points are confirmed to be on this line, so 2x + y = 1 is definitely the answer

OpenStudy (anonymous):

yay thank you!!

jimthompson5910 (jim_thompson5910):

you're welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!