help @Luigi0210 @rmrjr22
Major axis: The longest diameter of an ellipse. Minor axis: The shortest diameter of an ellipse.
Yup.
formula for the ellipse has the major and minor axes' lengths encoded as the square root of the denominators...the major one is the square root of the bigger number
So what's the longest diameter in this one?
14 ?
not too sure on that one
If I'm not mistaken the major axis is a+b
that's right. I should clarify my statement: it's the semimajor and semiminor axes that are the square roots of the denominators
@whpalmer4 @rmrjr22 what do you think?
look at the denominator of both parts
x/a +y/b = 1 simple form
guys, look at the picture
if a> b then its horrizontal... if a<b then its vertical
(for major axis)
evaluate at x = 4: \[(y+8)^2/7^2 = 1\]\[(y+8) =\pm 7\]\[y = -1, y = -15\] so the thing is 14 units long from top to bottom
for the minor axis, evaluate at y = -8: \[(x-4)^2/6^2=1\]\[x-4=\pm 6\]\[x=-2,x=10\]so 12 units long right to left
just be glad it isn't one of those damn ellipses that's tilted at an angle :-)
so i was right?
Hm.. Kinda lost.
you were right!
yup u were
talk to me @Luigi0210 what's got you confused?
Hm, well the method you used.. the book just says take a and multiply it by 2.
Which gave the same answer
of course. I'm just computing the points on the ellipse where all of the string is used either along the x axis or the y axis, essentially...
Well alright.
I think of ellipses as special cases of circles, rather than the more usual circles are special cases of ellipses :-)
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