Question

Help Please!!!
Solve agebraically. Answer in interval notation
(x^3)-(4x^2)>0

Answer 1

start with
\[x^2(x-4)>0\] and then it should be real easy, since \(x^2\geq 0\) for all \(x\)

Answer 2

oh that's great! so what is the answer you think? I think i got (infinity,4)....;;; not sure

Answer 3

well, there is no such thing as \((\infty, 4)\) that is for sure

Answer 4

try
\[(4,\infty)\]

Answer 5

or it could be (-infinity,4)?

Answer 6

well im stucked again;;;

Answer 7

no it cannot be \((-\infty, 4)\) since you are solving
\[x-4>0\]

Answer 8

so the final answer could be (4,infinity)?