What is the slope of the line that passes through (2, 5) and (–1, 5)? –3 0 undefined 3
i got 1/-3
but i'm not sure what the answer would be
y2-y1/x2-x1
= m (slope)
i got 1/-3 as my slope
(5-5)/(-1-2) = 0/-3
y coordinates are the same, so the line is horizontal and the slope is zero
oh crap aahaha
wait i dont understand
the y coordinates are both 5
i know the slope is 0/-3 but how do i figure out if it's undefined or not
they cancel out wouldnt it be undefined?
|dw:1372390572548:dw|
ah, gotcha...
the slope measures the steepness of the line but in this case the line is horizontal, as \(x\) increases by 1 unit, y stays the same, so the slope is zero over one, don't go up or down at all
rise/run = slope
there is no rise, but a run
(2, 5) and (–1, 5) gradient of line or slope : (y2 - y1) / (x2 - x1) (2, 5) let x1 represent 2 let y1 represent 5 (-1, 5) let x2 represent -1 let y2 represent 5 now using equation: (5 - 5) / (-1 - 2) = 0/-3
so its 0
@pamelasaucedo \(\frac{0}{\text{some number}}\) is \(0\)
so is it 0 or undefined? you guys are confusing me lol
0
gradient is 0. therefore the line is parallel to the x axis
a fraction with zero in the numerator (top) is zero
oh alright i get it now
a fraction with zero in the denominator is undefined
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