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Mathematics 16 Online
OpenStudy (anonymous):

a study determined that 17% of a population use a certain brand of laundry detergent. What is the probability that more than 2 shoppers selected at random from 11 shoppers use that brand of detergent?

OpenStudy (anonymous):

another binomial

OpenStudy (anonymous):

\[P(x=k)=\binom{n}{k}p^k(1-p)^{n-k}\]with \[n=11,k=2,p=.17,1-p=.83\]

OpenStudy (anonymous):

you got this or no? "more than 2" means you have to compute \[P(x=0) , P(x=1), P(x=2)\]add them up and then subtract the answer from 1

OpenStudy (anonymous):

ooo i was just calculating it with K = 2

OpenStudy (anonymous):

i got 0.716074 by adding x =0 , x = 1 x=2.. whereas the answer is .2839

OpenStudy (anonymous):

you have to subtract from 1

OpenStudy (anonymous):

it is "more than 2" so you compute 0, 1, and 2, then subtract the result from 1

OpenStudy (anonymous):

which is much easier than computing 3, 4, 5, 6, 7, 8, 9,10, 11 and adding all that up!

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