find the sum of this infinite geometric series: 100+60+36+...
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OpenStudy (anonymous):
It's fairly obvious to see that the common ratio is:\[\bf Common \ ratio = \frac{60}{100}=\frac{36}{60}=\frac{3}{5}\]So the geometric series is given by ('a' is the first term; 'r' is the common ratio):\[\bf ar^{n-1}=100\left( \frac{ 3 }{ 5 } \right)^{n-1}\]Since this geometric series is convergent, i.e. \(\bf |r| < 1\), the sum of the series is given by:\[\bf S_n=\frac{ a }{ 1-r }\]Can you evaluate the sum?
@mathisfun13
OpenStudy (mathisfun13):
uhmm i think so
OpenStudy (mathisfun13):
is the r my 3/5?
OpenStudy (mathisfun13):
....
OpenStudy (zzr0ck3r):
yes
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OpenStudy (mathisfun13):
so whats my Sn
terenzreignz (terenzreignz):
I think the formula has already been neatly provided :)
\[\Large S_n=\frac{a}{1-r}\]
Where r is the common ratio and a is the first term in the series :)
OpenStudy (mathisfun13):
ooh okay so 100 would be my a
OpenStudy (zzr0ck3r):
correct
terenzreignz (terenzreignz):
Yup :)
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