Find the sum of the following infinite geometric series, if it exists. one-third plus one-ninth plus one-twenty-seventh + one-eighty-first plus and so on
Find the sum of the following infinite geometric series, if it exists. 4 + 3.2 + 2.56 + 2.048 + …
don't use decimals:) 1/3+1/9+1/27....take the second divided by the first term what do you get?
wait, is this two questions?
no
how does 4 + 3.2 + 2.56 + 2.048 + relate to 1/3+1/9...?
sorry those are two different questions
1/9)/1/3 = 1/3 so your ratio is 1/3 first term is 1/3 so \[\frac{\frac{1}{3}}{1-\frac{1}{3}}\]
so 1/3 is the answer
We observe that the common ratio is the ratio of the successive and the previous term:\[\bf Common \ ratio=\frac{ \frac{ 1 }{ 9 } }{ \frac{ 1 }{ 3 } }=\frac{ \frac{ 1 }{ 27 } }{ \frac{ 1 }{ 9 } }=\frac{ 1 }{ 3 }\]So the geometric series is given by ('a' is the first term; 'r' is the common ratio):\[\bf ar^{n-1}=\frac{ 1 }{ 3 }\left( \frac{ 1 }{ 3 } \right)^{n-1}\]We observe that the series is convergent, i.e. \(\bf |r|<1\), so the sum of the series will be given by:\[\bf S_n=\frac{a}{1-r}\]Can you evaluate the sum? @dedog55
\[\frac{\frac{1}{3}}{1-\frac{1}{3}}=\frac{\frac{1}{3}}{\frac{2}{3}}=\frac{1}{3}*\frac{3}{2}=\frac{1}{2}\]
Find the sum of the following infinite geometric series, if it exists. 4 + 3.2 + 2.56 + 2.048 + …
what is the ratio?
I don't know how to do do this
yes you do.
divide the second term by the first
that is your ratio...
what is the ratio?
1.25
3.2/4 = 1.25??????
ya
nope...the top is smaller than the bottom so its less than one
no its .8
yes
ok so what is the first term?
4
\[\frac{firstterm}{1-ratio}=answer\]
is it 3.2
\[\frac{4}{1-0.8}=\frac{4}{0.2}=?\]
how did you get 3.2?
I did it wrong
its 20 hahaha
What is the r value of the following geometric sequence? 40, 20, 10, 5,…
so what part of divide the second term by the first are you not getting?
and....we already went over this problem:)
sorry not trying to be mean, but you ask the same question over and over with different numbers:) so lets get to why :)
sorry I sent you the wrong problem
Find two geometric means between 5 and 135.
you should close this and open another.
Join our real-time social learning platform and learn together with your friends!