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Verify the identity. (1 - sinx)/cosx = cosx/(1 + sinx)
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hi @IBhardcore :) for your identity, what you can do as a first step is multiply and divide by 1+sin x \(\large \dfrac{1-\sin x}{\cos x} \: \dfrac{1+\sin x}{1+\sin x}\) now can you simplify the numerator ?
sin ^2x + 1?
you sure ? hint : \((a+b)(a-b) = a^2-b^2 \\ (1-\sin x )(1+\sin x)=...?\)
1 - sin^2x
correct! and using \(\sin^2 x+\cos^2 x =1\) what does 1 - sin^2x simplify to ???
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cos^2x
good! now numerator has cos^2 x = cos x * cos x denominator has cos x (1+ sin x) notice that one cos x gets cancelled! what remains ?
cos x / 1+ sin x !
good! you got it :)
Thanks!! :)
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welcome ^_^
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