Mathematics
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OpenStudy (anonymous):
3, -13, and 5 + 4i
f(x) = x4 - 8x3 - 12x2 + 400x - 1599
f(x) = x4 - 200x2 + 800x - 1599
f(x) = x4 - 98x2 + 800x - 1599
f(x) = x4 - 8x3 + 12x2 - 400x + 1599
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OpenStudy (anonymous):
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form.
ganeshie8 (ganeshie8):
lets do this in unconventional way
OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
5+4i is one root so ?
OpenStudy (anonymous):
5-4i is also one
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ganeshie8 (ganeshie8):
list all the roots once
OpenStudy (anonymous):
3, -13, 5-4i and 5+4i
ganeshie8 (ganeshie8):
\(\alpha + \beta + \gamma + \psi = \frac{-b}{a} \)
ganeshie8 (ganeshie8):
sum of roots equals that. Now just dont get confuse yet, just add all the roots u listed, and tell me wat u get
OpenStudy (anonymous):
f(x) = x4 - 200x2 + 800x - 1599
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ganeshie8 (ganeshie8):
I want you add all the roots you listed and see wat u get
ganeshie8 (ganeshie8):
sum of roots :
3 + -13 + 5-4i + 5+4i = ?
OpenStudy (anonymous):
10
OpenStudy (anonymous):
-10
ganeshie8 (ganeshie8):
check again
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OpenStudy (anonymous):
ahhhh
OpenStudy (dan815):
>_>
OpenStudy (dan815):
ZERO
ganeshie8 (ganeshie8):
yess
ganeshie8 (ganeshie8):
so 0 = -b/a, => b = 0
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OpenStudy (anonymous):
yes
ganeshie8 (ganeshie8):
there will not be x^3 term in the polynomial.
OpenStudy (anonymous):
ok
ganeshie8 (ganeshie8):
So, answer is either B or C
OpenStudy (anonymous):
yep
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ganeshie8 (ganeshie8):
lets figure out the x^2 coefficient
ganeshie8 (ganeshie8):
Ive told you this is unconventional way, so if u dont get it, its okay :)
OpenStudy (anonymous):
ok, how do you do that
OpenStudy (dan815):
why does this work all the time?
ganeshie8 (ganeshie8):
\(\alpha \beta + \beta \gamma + \gamma \psi +\psi \alpha = \frac{c}{a}\)
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OpenStudy (dan815):
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