Question

Simplify completely 40v^2 20V^3
----- ÷ ----- = ?
35v^4 5v

Answer 1

cancel the terms with 5 and the poewrs accordingly

Answer 2

so cancel everything by 5 and v

Answer 3

@shkrina

Answer 4

No,can't cancel until you make a common denominator.

Answer 5

examples please

Answer 6

so is it 2
----
7v^4

Answer 7

can you teach me ? lol @shkrina
whats thre common denominator ? 7v^2 ?

Answer 8

\[\large \frac{40v^2}{35v^4}+\frac{20v^3}{5v}\] make a common denominator by multiplying the second fraction with 7v^3 \[\large \frac{40v^2}{35v^4}+\frac{140v^6}{35v^4}\]combine into one fraction \[\large \frac{40v^2+140v^6}{35v^4}\]factor out a 20v^2 from numerator \[\large \frac{20v^2(20 + 7v^4)}{35v^4}\]Now simplify \[\large \frac{4(20 + 7v^4)}{7v^2}\]

Answer 9

@Jhannybean have explained hope understand that ..... ..hope u r cleared....

Answer 10

Now distribute the 4. \[\large \frac{80+28v^4}{7v^2}\] divide each term in the numerator with the denominator. \[\large \frac{80}{7v^2}+4v^2\]

Answer 11

so its 80+28v^4
---------
7v^2

Answer 12

yep.

Answer 13

now i ?

Answer 14

@Jhannybean i hope its 8 not 80

Answer 15

i think it is 8...

Answer 16

Ohyes you are right, Sorry about that.\[\large \frac{20v^2(2 + 7v^4)}{35v^4}\]

Answer 17

then itll be 2
----
7v^4 ?

Answer 18

\[\large \frac{4(2+7v^4)}{7v^2}\]

Answer 19

insted of doing this long process u can directly cancel by 5 and the powers u will get the same ans now do LCM

Answer 20

8+28v^4
---------
7v^2

Answer 21

\[\large \frac{8+28v^4}{7v^2}\]

But it's not the proper way, you can't cancel stuff out in the fractions unless you factor stuff out.

Answer 22

so now what ?
these are the answer choices btw

2/7v^4

7/32

7v^4/32

32/7

Answer 23

u r cancelling the stuff of one fraction 45/35 and 20/5 sperately with its own denominator

Answer 24

\[\large \frac{8+28v^4}{7v^2}= \frac{8}{7v^2}+\frac{28v^4}{7v^2}\] reduce.

Answer 25

Ok. \[\large \frac{4(2+7v^4)}{7v^2}\]

Answer 26

thats not the answer right ?

Answer 27

Your answer choices should contain the variable v^2

Answer 28

well wats the ans ??

Answer 29

you guys put adding when i put division

Answer 30

i put a division sign and when you rewrote it, it had an adding sign

Answer 31

ooo well sorry .... fine reverse the fraction 20v^3/5v and then cancellation ...

Answer 32

Oh, oops. That was a division sign wasnt it...

Answer 33

yes lol

Answer 34

\[\frac{ 40v ^{2} }{ 35v ^{4} }*\frac{ 5v }{20v ^{3} }\]

Answer 35

There you go.

Answer 36

do you cross multiply when you flip them ?

Answer 37

s

Answer 38

You don't have to now, you can cancel.

Answer 39

so by 5

Answer 40

s

Answer 41

wait

Answer 42

8v^2/7v^4 x v/4v^3

Answer 43

lol thank you(:

Answer 44

2/7^4 ... all done

Answer 45

good job.