Question

Given f(x) = x^2/2-x, find f(1-i√2)
Please Help

Answer 1

I tried so many ways but I just can't get it Please help

Answer 2

There are 4 choices It could be
A. -3-2i√2
B. (-5-i√2)/3
C. (-7-5i√2)/3
D. (-7+5i√)/3

Answer 3

Please help

Answer 4

f(x) = x^2/2-x, find f(1-i√2)
\[f(x)= \frac{ x ^{2} }{ 2-x }\]
\[i.e. f(1-i \sqrt{2})= \frac{ (1-i \sqrt{2}) ^{2} }{ 2-(1-i \sqrt{2}) }\]
\[=\frac{ 1+2i ^{2} -2i \sqrt{2}}{ 2-1+i \sqrt{2} }= \frac{1-2 -2i \sqrt{2}}{ 1+i \sqrt{2} }\]
\[= \frac{-1 -2i \sqrt{2}}{ 1+i \sqrt{2} }= -\frac{(1+ 2i \sqrt{2})}{ (1+i \sqrt{2}) }\]
(Now we will rationalize the denominator)
\[=-\frac{(1+ 2i \sqrt{2})}{ (1+i \sqrt{2}) }\times \frac{ (1-i \sqrt{2}) }{ (1-i \sqrt{2}) }\]
\[=-\frac{1+ 2i \sqrt{2}-i \sqrt{2}-4i ^{2}}{ (1-2i ^{2}) }\]
=\[=-\frac{1+ i \sqrt{2}+4}{ 1+2 } =-\frac{5+ i \sqrt{2}}{3}\] and this is the solution to the given problem.

Answer 5

Thus the option B is correct.

Answer 6

I am really sorry but I don't understand this at all.
Can you put it in simpler terms

Answer 7

There is no simpler way to understand this than this method. first of all u need to be aware with concept of complex numbers i.e. i^2 = -1. Except this general calculations has been used to solve it

Answer 8

In the given problem i have substituted the given value of x.

Answer 9

I tried that but I got a different answer then the choices above.

Answer 10

Follow the method i have posted here, you will definitely reach to your result.

Answer 11

Thank you so much