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Mathematics 14 Online
OpenStudy (anonymous):

Can someone explain how to do this so I understand? Factor completely: −6x3y + 9x2y2 − 12xy3

OpenStudy (mathstudent55):

Look at numbers 6, 9, and 12. Do they have a common factor?

OpenStudy (anonymous):

3? if that's what you mean

OpenStudy (mathstudent55):

yes

OpenStudy (mathstudent55):

Now look at x^3, x^2 and x. Do they have a common factor?

OpenStudy (anonymous):

uhm.. x??

OpenStudy (mathstudent55):

yes, again. good job so far. third q: what is the common factor of y, y^2, y^3?

OpenStudy (anonymous):

y

OpenStudy (mathstudent55):

good. Now you know you are going to factor out 3xy, so your answer will look like 3xy( )

OpenStudy (mathstudent55):

Now look again at the original polynomial. −6x3y + 9x2y2 − 12xy3 = 3xy( ) We need to fill in the parentheses.

OpenStudy (mathstudent55):

Let's work on one term of the original polynomial at a time. What do you multiply 3xy by to get -6x^3y? In other words what is -6x^3y/3xy?

OpenStudy (anonymous):

-2x^2y?

OpenStudy (mathstudent55):

Almost. No need for y, since you have a y in 3xy, and you need to end up with -6x^3y which also only has y, not y^2. So it's -2x^2

OpenStudy (mathstudent55):

We're here now: 3xy(-2x ) Next term is 9x^2y^2 What do you multiply 3xy by to get 9x^2y^2? In other words, what is 9x^2y^2/3xy?

OpenStudy (anonymous):

3xy?

OpenStudy (anonymous):

Would it be 3xy(−2x2 + 3xy − 4y2) ??

OpenStudy (mathstudent55):

correct

OpenStudy (mathstudent55):

Good job!

OpenStudy (anonymous):

Awesome ! Thank you soo much !! You made it much easier than it seems !!

OpenStudy (mathstudent55):

wlcm

OpenStudy (mathstudent55):

This kind of factoring is using the distributive property in reverse.

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