Question

You roll 2 dice. What is the probability that the sum of the dice is odd or 1 die shows a 4? A 6 X 6 table of dice outcomes will help you to answer this question. Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms.

Answer 1

Total number of possible outcomes = 6^2 = 36
Sum of the digits---No. of outcomes
02 ------------------------- 01
03 ------------------------- 02
04 ------------------------- 03
05 ------------------------- 04
06 ------------------------- 05
07 ------------------------- 06
08 ------------------------- 05
09 ------------------------- 04
10 ------------------------- 03
11 ------------------------- 02
12 ------------------------- 01
Total --------------------- 36
P(sum of the digits is odd) = P(A) = (2+4+6+4+2) / 36 = 18/36
P(sum of the digits > 6) = P(B) = (6+5+4+3+2+1) / 36 = 21/36
P(A and B) = (6+4+2) / 36 = 12/36
Required probability = P(A or B) = P(A)+P(B)-P(A and B)
=18/36 + 21/36 - 12/36
= 27/36
= 3/4

Answer 2

now did that help?

Answer 3

so complicated but yes, i think so :)

Answer 4

well u askd Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms. right?

Answer 5

so u sumed up the numbers as in lowest terms"