Assuming all volume measurements are made at the same temperature and pressure, how many liters of water vapor can be produced when 8.23 liters of oxygen gas react with excess hydrogen gas? Show all of the steps taken to solve this problem. Balanced equation: 2 H2 (g) + O2 (g) 2 H2 O(g)
@chmvijay would help you :3 I'm sure
please helo @chmvijay
@chmvijay please!
@ganeshie8 can you please help me
@thomaster
\(\large\sf 2H_2 (g) + O_2 (g) \to 2 H_2 O(g)\) you have 8.23 liters of \(\large\sf O_2\) Do you know how to convert that to moles?
no i do not
Okay look at this diagram
You have the volume, you need moles For gasses, 22.4 L equals 1 mole So you have to divide your volume by 22.4 to get the amount of moles O2
okay i see
Do you know what the reaction ratio is for this reaction?
no i do not
2 moles of \(\sf H_2\) reacts with 1 mole of \(\sf O_2\) to produce 2 moles of \(\sf H_2O\) So the ratio is 2:1:2
alrighty whats afTer that
Now you know that you need 1 mole of O2 to produce 2 mol H2O so when you calculate the amount of moles O2 you have, you just multiply that with 2, and you'll have the amount of moles H2O that is produced
alright after that??
So do you know the amount of moles O2 you have?
no i do not lol
Like i told before, to get the amount of moles of a gas, divide the volume by 22.4 So for you its: \(\large\dfrac{8.23}{22.4}\)
so you have to divide to get the amount of moles in O2?
Yes :)
so that's 2.72
No you have to divide 8.23 by 22.4 :P not vice versa
ohhhhh so it's 0.36
yea 0.3674 to be more precise. So do you remember what to do now? think of the ratio
multiply by 2
exactly :)
so its 0.7348
Yes and now you have to go from mole to volume So not divide by 22.4 but multiply by 22.4 :)
so i multipy 0.7348 by 22.4?
Yes
i got 16.45952
Yes that's correct Now what is 8.23 multiplied by 2?
16.46
so that's the answer? :)
Yea :) do you understand this mole ratio now? A shortcut is to just multiply the liter gas it by 2 :P but that only works for gasses
yes i understand now! thank you so much :)
great job!
save the mole conversion diagram, it can be very helpful in chemistry
sorry i was offline :)
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