Math help to test out of Alg 2, review work: equation in the comments!

Question

andriod09 · Answer

$$(y - 1)(y^2 + 2y + 1)$$

anonymous · Answer

what are we trying to do here?

andriod09 · Answer

Have to solve the polynomal by distributing.

jhannybean · Answer

Use the method of grouping. $$\large (y)(y^2+2y+1) -(1)(y^2+2y+1)$$

jhannybean · Answer

$$\large y^3 +2y^2 + y -y^2 -2y -1$$ Can you simplify that?

andriod09 · Answer

Question, if you have $$(y)(y^2)$$ wouldn't that be $$2y^2$$?

jhannybean · Answer

Nope.

jhannybean · Answer

$$\large y\cdot y^3 = (1\cdot 1) \cdot y^ {1+2}$$

jhannybean · Answer

@Loser66 I guess distributing just helps break down the equation into simplified components. Good enough to evaluate.

jhannybean · Answer

I don't know if we do have to factor again, he just asked to simplify the equation?

loser66 · Answer

@Jhannybean read the 3rd comment :"I have to  solve...."

jhannybean · Answer

@andriod09 $$\large 2y^2 = y\cdot 2y =  (2\cdot 1)\cdot y^{1+1}$$

andriod09 · Answer

I have to put it into lowest terms. yes, i saw it. I'm letting you two finish your discussion. >.<

jhannybean · Answer

And @Loser66 I'm just doing what i think is the easiest method :P

jhannybean · Answer

@completeidiot

loser66 · Answer

@Jhannybean we have to know what we are supposed to do first, right?

anonymous · Answer

you cant solve for x because its not an equation

jhannybean · Answer

How would you go about solving this? @Loser66

anonymous · Answer

i would agree with jhanny's method to just expand the expression because question did not say to factor

loser66 · Answer

because the asker said at the 3rd comment:"I have to solve...", re read, please

andriod09 · Answer

@Loser66 I clarified that by solving, i had to simplify it.

jhannybean · Answer

Solving doesn't necessarily mean solving for a variable.... it might as well mean factor it to the simplest form.

jhannybean · Answer

Shall we continue, @andriod09

andriod09 · Answer

Its a polynomal, which i just recently figured out, as I got it wrong when i solved for x.

andriod09 · Answer

Yes, please.

jhannybean · Answer

And so to clarify this,we're just trying to simplify this problem into the most basic form, yes?

andriod09 · Answer

Yes, we're simplifying.

jhannybean · Answer

so what do you get when you simplify this? $$\large y^3 +2y^2 + y -y^2 -2y -1$$

andriod09 · Answer

OKay, give me a minute, i have got to switch brosers, this one is lagging hard. Brb.

andriod09 · Answer

BAck. Wouldn't you get: $$2y^3-1$$? i added up the $$y^3 + 2y^2 + y$$ which gave me: $$4y^5$$ then i subtracted $$3y^2$$ Is that right?

jhannybean · Answer

No. These are all different like terms...

andriod09 · Answer

What do you mean?

jhannybean · Answer

Just remember - the only timewe an add powersis when we're multiplying 2 terms. 

ex:   $\large y \cdot y^3 = y^{3+1}$

jhannybean · Answer

time we can add*

jhannybean · Answer

So here, you would have $$\large y^3 +2y^2 + y -y^2 -2y -1$$$$\large y^3 +(2y^2 -y^2)+(-2y +y) -1$$

andriod09 · Answer

So would That be the answer?

jhannybean · Answer

Simplify it.

andriod09 · Answer

How?

anonymous · Answer

adding and subtracting like terms

jhannybean · Answer

$$\large y^3 +(2y^2 -y^2)+(-2y +y) -1$$$$\large (1)y^3 +y^2(2-1)+y(-2+1)-1$$ Now you can reduce that i'm sure.

andriod09 · Answer

would it be: $$y^3 + 2y^2 - y^2 - 2y + y -1$$?

jhannybean · Answer

you can reduce 2y^2 -y^2 and -2y +y like i showed you above ^^

andriod09 · Answer

If you haven't I REALLY hate polynomals. I don't understand them.

jhannybean · Answer

Just evaluate this.....$$\large (1)y^3 +y^2(2-1)+y(-2+1)-1$$ you'll be done.

andriod09 · Answer

I don't get it still. What do i do to it? because every time i try to do something, its wrong.

jhannybean · Answer

Are yu getting $$\large y^3 +y^2 -y-1$$

andriod09 · Answer

No. I"m not. I'm getting what I told you.

jhannybean · Answer

Ok... $$\large y^3 + \color{red}{2y^2 - y^2}\color{blue}{ - 2y + y} -1$$ you can simplify these because these two highled portions are "like-terms" they both have the same power.

andriod09 · Answer

Oh, so they would cancel each other? I "knew" that. >.<

jhannybean · Answer

$$\large 2y^2 -y^2$$ are BOTH to the power of 2, and because these polynomials are ADDING eachother they can be simplified.

andriod09 · Answer

Ohhhhhhh. I'm stupid.

jhannybean · Answer

Nah,Probably just a brain fart.

jhannybean · Answer

Do you get how to reduce it now?

andriod09 · Answer

Yes. Time to go be a jerk to my other problems. I'll be back if i need more help

jhannybean · Answer

Sure thing :)

andriod09 · Answer

So wait, what is the answer? My STM just kicked in.

jhannybean · Answer

STM?

jhannybean · Answer

$$\large y^3 +y^2 -y-1$$ would be the most simplified form.

andriod09 · Answer

Ah okay. Thanks.

andriod09 · Answer

I'l pm you what STM means.