Find all solutions to the equation. (sin x)(cos x) = 0
either sin x = 0 or cos x 0
this is due to the zero property of multiplication
These are the options they gave me:
Would it be the first one?
so, at what points are sin(x) = 0 and cos(x) = 0?
check your Unit Circle, if you don't have one, you'd need one, many online
It would be the second one then right?
Because 0 is at 0, pi/2, pi, and 3pi/2
yes, the notation pretty much is just saying, every \(\large \frac{\pi}{2}\) increment onwards
and yes, at ever \(\frac{\pi}{2}\) either sine or cosine will zero out
Or would it be the 4th one because that one says every pi/2
those 2 look identical to me :/
The second option is pi/2 + n pi & n pi The fourth one is just pi/2 + n pi
yes, but the restrictions application seem to be exactly the same for the exact same elements
Which do you think would be a better answer then?
the 2nd one is just more redundant
I think the second one instead of the fourth but I'm not sure
I see nothing wrong with either, but I guess go for the redundant one heheh
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