Find all solutions in the interval [0, 2π).

4 sin2 x - 4 sin x + 1 = 0

Question

Find all solutions in the interval [0, 2π).

4 sin2 x - 4 sin x + 1 = 0

campbell_st · Answer

its basically a quadratic equation that can be factorised

(2sin(x) -1)^2 = 0

so you need to solve 

2sin(x) -1 = 0

consider the domain when looking for solutions.. as there are 2 answers.

anonymous · Answer

so sin x = 1/2?
I'm still confused as to how you got there...

anonymous · Answer

@campbell_st

loser66 · Answer

let t= sinx , so you have sin^2x = t^2, right? replace to the equation, you have 
4t^2 -4t +1=0, solve for t, then plug back to t = sinx , solve for x , don't forget interval

anonymous · Answer

Oh! That makes sense. Thank you!