Julie kicks a moose skin ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately, how long does it take until the moose skin ball hits the ground again? 0.6 sec 0.8 sec 1.6 secs 2.8 secs please help...
use the equations of motion with constant accleeration
s = ut + 0.5gt^2
what are the equations if you dont mind:)
s = displacement = 0 g = -32 ft/s62 and u = 25 ft/s
0 = 25t - 16t^2 solve for t
cwrw238 you are so wrong that newton cam back to life and died again
@cwrw238
so what would the answer be
Michelle i would like to help you but i think that the data is incomplete...
but that is how the question is written out what am suppose to do? i could go back and reread the lesson
yes you should you dont even know what equations of motion are
you see this is my third time taking this class and i really don't want to fail again.
Ahaha michelle take it easy!
i think I will, look over the lesson again,but what do you guys think would be the best way to approach it.
with love
:)
The problem that i am having is the fact that they didnt mention at which point in height the balls stops and starts falling back
yeah, i guess, i could always email my teacher about it because there are alway's glitches like that happening in the tests.
cwrw238 already said it solve 0 = 25t - 16t^2 for t to get your answer (it will be the root that is not 0)
um ok, i will go back and do it that way.
thanks for the advice everyone, you all have been great so you have a nice day
YOU HAVE TO USE SEQENCES EVERTHING ELSE IS WRONG!!!!!!!!!!!!!!
Good luck!
16t^2 - 25 = 0 t(16t - 25) = 0 16t = 25 f = 25/16 = 1.6
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