Question

Factor each Polynomial Completely

3x^2y-11xy+8y

Answer 1

Hey there.

Answer 2

first pullout the LCM between all terms,which is y.

Answer 3

hey there, do you know how to do these?

Answer 4

LMC means lowest Common Multiple? Right?

Answer 5

\[\large 3x^2 \color{green}y-11x\color{green}y+8\color{green}y\] see how y multiplies toallof these. So if you factor it out, you will get \[\large \color{green}y(3x^2 - 11x +8)\]

Answer 6

Yes,lowest common multiple.

Answer 7

okay so thats my answer?

Answer 8

No...

Answer 9

Now we want to simplify whats inside the parenthesis.

Answer 10

so it would be -8x^2+8?

Answer 11

no?..

Answer 12

so what then?

Answer 13

\[\large \color{green}3x^2-11x+\color{green}8\]We'vegot these two highlighted numbers, multiply them, and we get \[\large x^2 -11x +24\] Now we ask ourselves what two numbers multiply to give +24 and add to give -11?

Answer 14

We get \[\large (x-8)(x-3)\] Now that we've factored it out,we use our leading coefficient, 3, to divide each of these terms. \[\large (x-\frac83)(x-\frac33)\]we see what we can reduce in these two terms. \[\large (x-\frac83)(x-1)\] because 8/3s cannot be reduced,we multiply it to the x. \[\large (3x-8)(x-1)\] that is our reduced form.

Answer 15

So our whole function becomes \[\large \color{green}y(3x^2 - 11x +8) = y(3x-8)(x-1)\]

Answer 16

sorry, \[\large y[(3x-8)(x-1)]\]

Answer 17

which is equivalent to your previous response

Answer 18

can you help me with some more?

Answer 19

\[9x^2+30x+25\]

Answer 20

sorry i read that wrong hang on and i will

Answer 21

did you learn anything from your previous question? :(