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If G(F(x))=x^2-3, and G(x)= x-3, find F(3)
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somebody help me please!!
well is just a function composition $$g(f(x)) = x^2-3\\ g(x)= x-3 $$ so, what's f(x)? f(x) is whatever was INPUT to make "x" in x-3, to \(x^2-3\)
so $$ g(x) = x-3\\ f(x) = \color{red}{x^2}\\ g(f(x)) = g(\color{red}{x^2}) = (\color{red}{x^2})-3 $$
so, since your $$ f(x) = \color{red}{x^2}\\ f(-3) = \color{red}{\square?}^2 $$
ohh is just 3 ahem
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so $$ f(x) = \color{red}{x^2}\\ f(3) = \color{red}{\square?}^2 $$
i'm just not seeing where the x^2 comes from,
g(x) = x-3 g( SOMETHING ) = ( SOMETHING ) -3 g ( f(x) ) = \(x^2 -3\)
oh i see it now
thank you for your help
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yw
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