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Simplify the radical expression.
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A. 16
C. 10
Can you breakdown the prime number of 128.
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Hint: 128 = 2 x 64
\[2\sqrt{64}\] like that?
\[\sqrt(64*2) = \sqrt(64)*\sqrt(2)\]
So I can take that and reduce it?
I'd take it down to 32, then down to 16
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SO Id go with A
Break up the square roots using the identity \[\sqrt{x*y}=\sqrt{x}*\sqrt{y}\]
if you take the square root of 64 you'll end up with ?
8
correct
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So B then
evaluate \[ \sqrt(64)*\sqrt(2)\]
128?
in square root
\[\sqrt{128}\]
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\[8*\sqrt2\]
the expression √128 simplifies to 8∗√2
therefore, the answer is B not A :)
you were incredibly helpful. Thank you
yw ^_^
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