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Mathematics 9 Online
OpenStudy (explainitlikeimfive):

Simplify the radical expression.

OpenStudy (explainitlikeimfive):

OpenStudy (explainitlikeimfive):

A. 16

OpenStudy (explainitlikeimfive):

C. 10

OpenStudy (explainitlikeimfive):

OpenStudy (zale101):

Can you breakdown the prime number of 128.

OpenStudy (zale101):

Hint: 128 = 2 x 64

OpenStudy (explainitlikeimfive):

\[2\sqrt{64}\] like that?

OpenStudy (zale101):

\[\sqrt(64*2) = \sqrt(64)*\sqrt(2)\]

OpenStudy (explainitlikeimfive):

So I can take that and reduce it?

OpenStudy (explainitlikeimfive):

I'd take it down to 32, then down to 16

OpenStudy (explainitlikeimfive):

SO Id go with A

OpenStudy (zale101):

Break up the square roots using the identity \[\sqrt{x*y}=\sqrt{x}*\sqrt{y}\]

OpenStudy (zale101):

if you take the square root of 64 you'll end up with ?

OpenStudy (explainitlikeimfive):

8

OpenStudy (zale101):

correct

OpenStudy (explainitlikeimfive):

So B then

OpenStudy (zale101):

evaluate \[ \sqrt(64)*\sqrt(2)\]

OpenStudy (explainitlikeimfive):

128?

OpenStudy (zale101):

in square root

OpenStudy (explainitlikeimfive):

\[\sqrt{128}\]

OpenStudy (zale101):

\[8*\sqrt2\]

OpenStudy (zale101):

the expression √128 simplifies to 8∗√2

OpenStudy (zale101):

therefore, the answer is B not A :)

OpenStudy (explainitlikeimfive):

you were incredibly helpful. Thank you

OpenStudy (zale101):

yw ^_^

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