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Mathematics 19 Online
OpenStudy (anonymous):

Factor each polynomial Completely

OpenStudy (anonymous):

\[9x^2+30x+25\]

OpenStudy (bahrom7893):

that looks to me like a perfect

OpenStudy (bahrom7893):

square

OpenStudy (bahrom7893):

a^2+2ab+b^2

OpenStudy (bahrom7893):

What would your a be in this case?

OpenStudy (bahrom7893):

\[(\space\space\space)^2=(a)^2\]

OpenStudy (bahrom7893):

What's gonna go inside the parenthesis?

OpenStudy (anonymous):

9?

OpenStudy (bahrom7893):

no, what value squared will give you \[9x^2\]

OpenStudy (anonymous):

@Jhannybean can you do this one like you did the last one or not?

OpenStudy (anonymous):

@bahrom7893 3?

OpenStudy (bahrom7893):

no (3x)^2

OpenStudy (jhannybean):

lets see.

OpenStudy (jhannybean):

\[\large 9x^2 +30x+25\] this function takes on the form \(\large (a^2 +b^2)= (a+b)(a+b)\) So lets begin by splitting up our function we have 9x^2 and 25. these are our \(a^2\) and \(b^2\) .\[\large a = \sqrt{9x^2} = 3x\]and \[\large b = \sqrt{25} = 5\] so what we do is write it out in the form \(\large (a+b)(a+b)\)\[\large (3x+5)(3x+5) = (3x+5)^2 =9x^2+30x+25\]

OpenStudy (jhannybean):

Sorry. i was wrong in the fact that \[\large (a+b)^2= (a+b)(a+b)=a^2+2ab+b^2 \]

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