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OpenStudy (anonymous):
\[9x^2+30x+25\]
OpenStudy (bahrom7893):
that looks to me like a perfect
OpenStudy (bahrom7893):
square
OpenStudy (bahrom7893):
a^2+2ab+b^2
OpenStudy (bahrom7893):
What would your a be in this case?
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OpenStudy (bahrom7893):
\[(\space\space\space)^2=(a)^2\]
OpenStudy (bahrom7893):
What's gonna go inside the parenthesis?
OpenStudy (anonymous):
9?
OpenStudy (bahrom7893):
no, what value squared will give you \[9x^2\]
OpenStudy (anonymous):
@Jhannybean can you do this one like you did the last one or not?
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OpenStudy (anonymous):
@bahrom7893
3?
OpenStudy (bahrom7893):
no
(3x)^2
OpenStudy (jhannybean):
lets see.
OpenStudy (jhannybean):
\[\large 9x^2 +30x+25\] this function takes on the form \(\large (a^2 +b^2)= (a+b)(a+b)\)
So lets begin by splitting up our function
we have 9x^2 and 25. these are our \(a^2\) and \(b^2\) .\[\large a = \sqrt{9x^2} = 3x\]and \[\large b = \sqrt{25} = 5\] so what we do is write it out in the form \(\large (a+b)(a+b)\)\[\large (3x+5)(3x+5) = (3x+5)^2 =9x^2+30x+25\]
OpenStudy (jhannybean):
Sorry. i was wrong in the fact that \[\large (a+b)^2= (a+b)(a+b)=a^2+2ab+b^2 \]