Question

put the answers in slope-intercept and standard form:

vertical and contains (-4,6)

Answer 1

i know that i could use the equation y2-y1 over x2-x1. -4 would be x1 and 6 would be y1. but what about x2 and y2?

Answer 2

the equation for a vertical line is x=c (slope is undefines) but what variables would i plug in?

Answer 3

Don't use that to find it - you can't, considering you're only given 1 point.
Instead, realise that because the line is vertical, it can only have 1 x-value. Considering what the x-value is, then you should realise that x=(x value) is the equation of the line. You can rearrange it to have all numbers on one side being equal to 0 to find the standard form.

Answer 4

Oops, I meant that as a reply to your first comment. Yes, you use x=c

Answer 5

what does c stand for?

Answer 6

so if -4 is x, i can put that into the equation: -4=c. what does that mean?

Answer 7

No, because x is a variable - you should put c = -4. When you have a point, the x and y values are not subbed into the "variable" positions in the line equation.

Answer 8

x=-4

Answer 9

When the line x = -4, if you imagine it, it's a vertical line where all the x values of it are -4 and it has infinite y values.

Answer 10

where does the 6 come into play?

Answer 11

It doesn't. It's just one of the many infinite points on the line. If they would have given you the point (-4, 1000), the line would still be x = -4

Answer 12

but how would i solve for the slope with just that one equation?