Question

solve

plse help me understand this question and help me to solve it

Answer 1

so draw it...@msingh

Answer 2

quadratic formula find x intercepts

Answer 3

can u help me

Answer 4

yes, find x intercepts

Answer 5

plot the two points in a coordinate grid

Answer 6

when y = 0, x = the points u just worked out
so ( , 0) ( , 0)

Answer 7

okay these will be vertex

Answer 8

In Geogebra software type the given eq of Hyperbola and it will immediately show you to plot it on the graph.

Answer 9

type the eq in input bar

Answer 10

i dont know where is geogebra software and how to use it

Answer 11

http://www.geogebra.org/cms/en/

Answer 12

what about vertex

Answer 13

\[f \left( x \right)=-4x ^{2}+4x+1=-4\left( x ^{2} -x\right)+1\]
\[f \left( x \right)=-4\left( x ^{2}-x+\frac{ 1 }{ 4 }-\frac{ 1 }{ 4 } \right)+1\]

\[f(x)=-4\left( x-\frac{ 1 }{ 2 } \right)^{2}+1+1\]

\[\left( x-1 \right)^{2}=-\frac{ 1 }{ 4 }\left\{ f \left( x \right)-2 \right\}\]

it is a downward para bola
its vertex is (1,2)

Answer 14

how ur last step came

Answer 15

what about graph

Answer 16

\[when x=0, y=f \left( x \right)=1\]
\[when y=f \left( x \right)=0,\left( x-\frac{ 1 }{ 2 } \right)^{2}=\frac{ -2 }{ -4 }=\frac{ {2} }{ 4 }\]
\[x=\frac{ 1 }{ 2 }\pm \frac{ \sqrt{2} }{ 2 }=\frac{ 1+\sqrt{2} }{ 2 },\frac{ 1-\sqrt{2} }{ 2 }= \frac{ 1+1.414 }{ 2} ,\frac{ 1-1.414 }{ 2 } \]
x=1.2,-0.2

Answer 17

correction
\[\left( x-\frac{ 1 }{ 2 } \right)^{2}=-\frac{ 1 }{ 4 }\left\{ f \left( x \right)-2 \right\}\]

Answer 18

\[vertex is \left( \frac{ 1 }{ 2 },2 \right)\]